By Barbara Jund

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**Additional info for Algebra success in 20 minutes a day**

**Sample text**

X–5+5=9+5 x + 0 = 14 x = 14 Example: a + 6 = 7 Subtract 6 from both sides of the equation. Simplify both sides of the equation. Add 0 to a. a+6–6=7–6 a+0=1 a=1 Example: y – 11 = 8 Add 11 to both sides of the equation. Simplify both sides of the equation. Add 0 to y. y – 11 + 11 = 8 + 11 y + 0 = 19 y = 19 Example: –r + 9 = 13 Subtract 9 from both sides of the equation. –r + 9 – 9 = 13 – 9 Simplify both sides of the equation. –r + 0 = 4 Add 0 to –r. –r = 4 Are you finished? No! The value of the variable must be positive, and r is negative.

37 – 12 ______67. –12 ÷ 4 ______80. –10 – 2 ______68. –9 + 12 ______81. –2 · –7 · –3 ______69. 16 – –5 ______82. 2 + 9 –11 + 3 ______70. –36 ÷ –18 ______83. 10 · –2 · –3 ______71. 7 · –8 ______84. –48 ÷ –3 ______72. –45 – 2 ______85. 20 – –3 + 8 – 11 ______73. –9 · –3 ______86. 2 · –2 · –4 ______74. –11 + –15 ______87. –10 – –4 ______75. 39 ÷ –3 ______88. 60 ÷ –5 ______76. –18 – –3 ______89. 4 · –5 · –2 · 10 ______77. –20 · 3 ______90. –10 + 5 – 7 – 13 Applications Represent the information in the problem with signed numbers.

46 Team-LRN – SOLVING EQUATIONS WITH VARIABLES ON BOTH SIDES OF THE EQUATION – Example: 5x + 3 = 3(x + 5) Use the distributive property. Subtract 3 from both sides of the equation. Simplify both sides of the equation. Subtract 3x from both sides of the equation. Simplify both sides of the equation. Divide both sides of the equation by 2. Simplify both sides of the equation. 5x + 3 = 3x + 15 5x + 3 – 3 = 3x + 15 – 3 5x = 3x + 12 5x – 3x = 3x – 3x + 12 2x = 12 2x 12 ᎏ ᎏ = ᎏᎏ 2 2 x=6 Example: 4x + 6 = –2(3x + 4) Use the distributive property.